# Number 6

There should be no "input"; weight is a parameter of the function.
There should be no printing; the string should be returned.

# Version from the solution
def cherries(weight):
   if weight >= 10.4:
      return '9 Row'
   elif weight >= 8.6:
      return '10 Row'
   elif weight >= 7.1
      return '11 Row'
   else:
      return '12 Row'

# following isn't wrong; but the tests are more complex than needed
def cherries(weight):
   if weight >= 10.4:
      return '9 Row'
   elif weight >= 8.6 and weight < 10.4:
      return '10 Row'
   elif weight >= 7.1 and weight < 8.6:
      return '11 Row'
   else:
      return '12 Row'

# This doesn't work; why?  Try it with argument 20.  The answer should be '9 row' but it is '11 row'
def cherries(weight):
   if weight >= 10.4:
      s = '9 Row'
   if weight >= 8.6:
      s = '10 Row'
   if weight >= 7.1:
      s =  '11 Row'
   if weight < 7.1:
      s = '12 Row'
   return s

# On the other hand, this works, even though it too uses if's instead of elifs:
def cherries(weight):
   if weight >= 10.4:
      return '9 Row'
   if weight >= 8.6:
      return '10 Row'
   if weight >= 7.1:
      return '11 Row'
   if weight < 7.1:
      return '12 Row'


# This doesn't work; why?  Try it with argument 5.  The answer should be '12 Row' but it is '10 Row'
def cherries(weight):
   if weight >= 10.4:
      return '9 Row'
   elif weight >= 8.6 or weight < 10.4:
      return '10 Row'
   elif weight >= 7.1 or weight < 8.6:
      return '11 Row'
   else:
      return '12 Row'


# For number 7, consider the condition in the while loop.
# It is supposed to be true if ans is anything other than "0" or "1"

while not (ans == "0" or ans == "1"):  #correct

while not ans == "0" and not ans == "1":  #correct

while ans != "0" and ans != "1": #correct

while not ans == "0" or ans == "1": # True if ans is "1"!    need ()'s 

while ans != '0' or ans != '1':  # this is true for ANY value of ans; try it!

while not ans == "0" or not ans == "1"  # this is true for ANY value of ans; try it!