def remove_i (s):
    '''Return a new string that is the same as s, but with all instances of 
    the letter i removed.'''
    
    while s.count("i") > 0:
        # remove the next occurrence of "i"
        where = s.find("i")
        # remove the character at position "where" in "s".
        s = s[0:where] + s[where+1:]
        
    return s


if __name__ == "__main__":
    text = "Indiana Illinois"
    print text
    text = remove_i(text)
    print text,"should be Indana Illnos"
    text = ""
    text = remove_i(text)
    print text,"should be the empty string"
    text = "aa bb cc dd"
    text = remove_i(text)
    print text,"should be aa bb cc dd"